[
next
] [
prev
] [
prev-tail
] [
tail
] [
up
]
4.6.2
problem 80
(a)
X
∼
FS
(
20
−
m
+
1
20
)
⇒
E
(
X
)
=
20
20
−
m
+
1
(b)
E
(
√
X
)
=
∑
x
∈
X
√
x
P
(
X
=
x
)
=
∑
20
i
=
1
√
i
(
m
−
1
20
)
i
−
1
20
−
m
+
1
20
[
next
] [
prev
] [
prev-tail
] [
front
] [
up
]