5.4.3 problem 28
Starting from the fact given in the problem
P(|Y−μ|<1.96σ)≈0.95
P(−1.96σ<Y−μ<1.96σ)≈0.95
P(Y−1.96σ<μ<Y+1.96σ)≈0.95
P(μ∈(Y−1.96σ,Y+1.96σ))≈0.95
Therefore, the random interval that contains
μ about 95% of
the time is (Y−1.96σ,Y+1.96σ).